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2 mole of an ideal gas at 27°C temperature is expanded reversibly from 2 l to 20 l. Find the entropy change (R = 2 cal/mol K).

1. 92.1
2. 0
3. 4
4. 9.2

Correct answer: 9.2

Solution

The entropy change for an ideal gas during reversible isothermal expansion is given by ΔS = nRln(V2/V1). Substituting n = 2, R = 2 cal/mol K, V1 = 2 L, and V2 = 20 L, we get ΔS = 2 × 2 × ln(20/2) = 9.2 cal/K.

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