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What is the entropy change (in J K⁻¹ mol⁻¹) when one mole of ice is converted into water at 0°C? (The enthalpy change for the conversion of ice to liquid water is 6.0 kJ mol⁻¹ at 0°C)
- 21.98
- 10.13
- 20.13
- 2.198
Correct answer: 21.98
Solution
The entropy change (ΔS) is calculated using the formula ΔS = ΔH/T. Here, ΔH = 6.0 kJ mol⁻¹ = 6000 J mol⁻¹ and T = 0°C = 273 K. Substituting, ΔS = 6000/273 ≈ 21.98 J K⁻¹ mol⁻¹.
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