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If the enthalpy change for the transition of liquid water to steam is 30 kJ mol⁻¹ at 27°C, the entropy change for the process would be:

1. 10 J mol⁻¹ K⁻¹
2. 1.0 J mol⁻¹ K⁻¹
3. 0.1 J mol⁻¹ K⁻¹
4. 100 J mol⁻¹ K⁻¹

Correct answer: 10 J mol⁻¹ K⁻¹

Solution

The entropy change (ΔS) is calculated using the formula ΔS = ΔH/T, where ΔH is the enthalpy change and T is the temperature in Kelvin. Converting 27°C to Kelvin gives T = 300 K. Substituting, ΔS = 30,000 J mol⁻¹ / 300 K = 100 J mol⁻¹ K⁻¹.

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