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The enthalpy of fusion of water is 1.435 kcal/mol. The molar entropy change for the melting of ice at 0°C is:

1. 10.52 cal/(mol K)
2. 21.04 cal/(mol K)
3. 5.260 cal/(mol K)
4. 0.526 cal/(mol K)

Correct answer: 10.52 cal/(mol K)

Solution

The molar entropy change (ΔS) is calculated using the formula ΔS = ΔH/T. Here, ΔH = 1.435 kcal/mol = 1435 cal/mol, and T = 273 K. Substituting, ΔS = 1435/273 = 10.52 cal/(mol K).

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