Exams › NEET › Chemistry

If ΔH is the change in enthalpy and ΔE, the change in internal energy accompanying a gaseous reaction, then

1. ΔH is always greater than ΔE
2. ΔH < ΔE only if the number of moles of the products is greater than the number of moles of the reactants
3. ΔH is always less than ΔE
4. ΔH < ΔE only if the number of moles of products is less than the number of moles of the reactants

Correct answer: ΔH < ΔE only if the number of moles of products is less than the number of moles of the reactants

Solution

The relationship between ΔH and ΔE is given by ΔH = ΔE + ΔnRT, where Δn is the change in the number of moles of gas. If the number of moles of products is less than the number of moles of reactants, Δn is negative, making ΔH < ΔE.

Related NEET Chemistry questions

• An ideal gas is compressed in a closed container its U?
• Internal energy does not include
• Assertion The change in internal energy and change in heat enthalpy does not depend upon the path by which changes are brought in. Reason Both \( \Delta U \) and \( \Delta H \) are path independent as U and H are state functions.
• Liquid benzene burns in oxygen according to: \( 2 C_{6} H_{6}+15 O_{2} \rightarrow 12 C O_{2}+6 H_{2} O \) If density of liquid benzene is \( 0.88 \mathrm{g} / \mathrm{cc} \) what volume of \( \boldsymbol{O}_{2} \) at \( \mathrm{STP} \) is needed to complete the combustion of 39 cc of liquid benzene?
• When a bomb calorimeter is used to determine the heat of reaction, which property of the system under investigation is most likely to remain constant?
• When heat is given to gas in an isothermal change, the result will be

⚔️ Practice NEET Chemistry free + battle 1v1 →