Exams › NEET › Chemistry

Given that C + O₂ → CO₂ : ΔH⁰ = -x kJ 2CO + O₂ → 2CO₂ : ΔH⁰ = -y kJ The enthalpy of formation of carbon monoxide will be

1. 2x - y
2. y - 2x
3. 2x - y
4. y - 2x

Correct answer: y - 2x

Solution

The enthalpy of formation of CO can be derived by reversing and combining the given reactions. Using Hess's Law, the enthalpy of formation of CO is calculated as ΔH = y - 2x.

Related NEET Chemistry questions

• An ideal gas is compressed in a closed container its U?
• Internal energy does not include
• Assertion The change in internal energy and change in heat enthalpy does not depend upon the path by which changes are brought in. Reason Both \( \Delta U \) and \( \Delta H \) are path independent as U and H are state functions.
• Liquid benzene burns in oxygen according to: \( 2 C_{6} H_{6}+15 O_{2} \rightarrow 12 C O_{2}+6 H_{2} O \) If density of liquid benzene is \( 0.88 \mathrm{g} / \mathrm{cc} \) what volume of \( \boldsymbol{O}_{2} \) at \( \mathrm{STP} \) is needed to complete the combustion of 39 cc of liquid benzene?
• When a bomb calorimeter is used to determine the heat of reaction, which property of the system under investigation is most likely to remain constant?
• When heat is given to gas in an isothermal change, the result will be

⚔️ Practice NEET Chemistry free + battle 1v1 →