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Enthalpy of CH₄ + 2O₂ → CH₃OH is negative. If enthalpy of combustion of CH₄ and CH₃OH are x and y respectively, then which relation is correct

1. x > y
2. x < y
3. x = y
4. x ≥ y

Correct answer: x > y

Solution

The enthalpy of the reaction CH₄ + 2O₂ → CH₃OH is negative, indicating it is exothermic. Since CH₃OH is more stable than CH₄, its combustion enthalpy (y) will be less negative than that of CH₄ (x), making x > y.

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