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Under isothermal condition, a gas at 300 K expands from 0.1 L to 0.25 L against a constant external pressure of 2 bar. The work done by the gas is [Given that 1 Bar = 100 J]

1. -30 J
2. 5 kJ
3. 25 J
4. 30 J

Correct answer: 30 J

Solution

The work done by the gas is calculated using the formula W = -P_ext × ΔV. Here, P_ext = 2 bar = 200 J/L, and ΔV = (0.25 - 0.1) L = 0.15 L. Substituting, W = -200 × 0.15 = -30 J. The negative sign indicates work done by the gas.

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