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The ground state electronic configuration of valence shell electrons in nitrogen molecule (N2) is written as KK σ2s2, σ*2s2, π2px2, π2py2, σ2pz2. Bond order in nitrogen molecule is:

1. 0
2. 1
3. 2
4. 3

Correct answer: 3

Solution

The bond order is calculated as (number of bonding electrons - number of antibonding electrons)/2. For N2, there are 10 bonding electrons and 4 antibonding electrons, so bond order = (10 - 4)/2 = 3.

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