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ExamsNEETChemistry

Bond order of 1.5 is shown by:

  1. O2+
  2. O2
  3. O2−
  4. O2

Correct answer: O2−

Solution

The bond order is calculated using the formula (Nb - Na)/2, where Nb is the number of bonding electrons and Na is the number of antibonding electrons. For O2−, the bond order is 1.5 as it has 11 bonding and 8 antibonding electrons.

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