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Four diatomic species are listed below. Identify the correct order in which the bond order is increasing in them:

1. NO < O2 < C2− < He2+
2. O2 < NO < C2− < He2+
3. C2− < He2+ < O2 < NO
4. He2+ < O2 < NO < C2−

Correct answer: He2+ < O2 < NO < C2−

Solution

Bond order is calculated using molecular orbital theory. He2+ has the lowest bond order (0.5), followed by O2 (2), NO (2.5), and C2− (3). Thus, the correct order is He2+ < O2 < NO < C2−.

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