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In BrF3 molecule, the lone pairs occupy equatorial positions to minimize:

1. lone pair - bond pair repulsion only
2. bond pair - bond pair repulsion only
3. lone pair - lone pair repulsion and lone pair - bond pair repulsion
4. lone pair - lone pair repulsion only

Correct answer: lone pair - lone pair repulsion and lone pair - bond pair repulsion

Solution

In BrF3, the molecule adopts a T-shaped geometry due to the presence of two lone pairs on the central bromine atom. These lone pairs occupy equatorial positions to minimize both lone pair-lone pair and lone pair-bond pair repulsions, as lone pair-lone pair repulsions are stronger.

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