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A metal oxide has the formula Zn2O3. It can be reduced by hydrogen to give free metal and water. 0.1596 g of the metal oxide requires 6 mg of hydrogen for complete reduction. The atomic weight of the metal is:
- 27.9
- 159.6
- 79.8
- 55.8
Correct answer: 79.8
Solution
The reaction involves Zn2O3 being reduced by hydrogen. Using stoichiometry, the molar ratio of Zn2O3 to H2 is 1:3. From the given data, calculate the molar mass of Zn using the mass of Zn2O3 and H2 consumed. The atomic weight of Zn is found to be 79.8.
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