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An organic compound containing C, H and N gave the following analysis: C = 40%; H = 13.33%; N = 46.67%. Its empirical formula would be:

1. C2H4N2
2. CH4N
3. CH2N
4. C2H2N

Correct answer: CH4N

Solution

To determine the empirical formula, divide the percentage composition of each element by its atomic mass: C (40/12 = 3.33), H (13.33/1 = 13.33), N (46.67/14 = 3.33). The simplest ratio is 1:4:1, giving CH4N as the empirical formula.

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