Exams › NEET › Chemistry

Percentage of Se in peroxidase anhydrase enzyme is 0.5% by weight (at. wt. = 78.4). The minimum molecular weight of peroxidase anhydrase enzyme is:

1. 1.568 × 10³
2. 15.68
3. 2.136 × 10⁴
4. 1.568 × 10⁴

Correct answer: 1.568 × 10⁴

Solution

The minimum molecular weight of the enzyme is calculated using the formula: (Atomic weight of Se / Percentage of Se) × 100. Substituting the values: (78.4 / 0.5) × 100 = 1.568 × 10⁴.

Related NEET Chemistry questions

• Which of the following statements is/are correct? This question has multiple correct options
• Calculate the \( \% \) composition of Carbon in \( C O_{2} . \) Molar mass is 44.01
• Which of the following rules regarding the significant figures and calculations involving them is not correct?
• \( 16.8 \mathrm{g} \) of metal carbonate on thermal decomposition gave 8 g of metallic oxide and \( 8.8 \mathrm{g} \) of carbon dioxide. They follow:
• Calculate the percent composition of carbon in \( C_{6} H_{12} O_{6} \)
• Which one of the followings has maximum number of atoms?

⚔️ Practice NEET Chemistry free + battle 1v1 →