Exams › NEET › Chemistry

The radioactive isotope ⁶⁰Co₂₇ which is used in the treatment of cancer can be made by (n, p) reaction. For this reaction the target nucleus is:

1. ⁵⁹Ni₂₈
2. ⁵⁹Co₂₇
3. ⁶⁰Ni₂₈
4. ⁶⁰Co₂₇

Correct answer: ⁵⁹Co₂₇

Solution

In an (n, p) reaction, a neutron is absorbed by the target nucleus, and a proton is emitted. To produce ⁶⁰Co₂₇, the target nucleus must be ⁵⁹Co₂₇, which absorbs a neutron to form ⁶⁰Co₂₇.

Related NEET Chemistry questions

• Which of the following statements is/are correct? This question has multiple correct options
• Calculate the \( \% \) composition of Carbon in \( C O_{2} . \) Molar mass is 44.01
• Which of the following rules regarding the significant figures and calculations involving them is not correct?
• \( 16.8 \mathrm{g} \) of metal carbonate on thermal decomposition gave 8 g of metallic oxide and \( 8.8 \mathrm{g} \) of carbon dioxide. They follow:
• Calculate the percent composition of carbon in \( C_{6} H_{12} O_{6} \)
• Which one of the followings has maximum number of atoms?

⚔️ Practice NEET Chemistry free + battle 1v1 →