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In the electrochemical cell : Zn|ZnSO4(0.01M)||CuSO4(1.0M)|Cu, the emf of this Daniel cell is E1. When the concentration of ZnSO4 is changed to 1.0M and that of CuSO4 changed to 0.01M, the emf changes to E2. From the followings, which one is the relationship between E1 and E2? (Given, RT/F = 0.059)

1. E1 < E2
2. E1 > E2
3. E2 = 0 ≠ E1
4. E1 = E2

Correct answer: E1 > E2

Solution

The Nernst equation shows that the emf of a cell depends on the concentration of the ions involved. When the concentration of ZnSO4 increases and CuSO4 decreases, the cell potential decreases, making E1 > E2.

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