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How many grams of cobalt metal will be deposited when a solution of cobalt (II) chloride is electrolyzed with a current of 10 amperes for 109 minutes? (Faraday = 96,500 C; Atomic mass of Co = 59)

1. 0.60
2. 4.0
3. 2.0
4. 40.0

Correct answer: 4.0

Solution

Using Faraday's laws of electrolysis, the mass deposited (m) is calculated as m = (Z × I × t), where Z = M / (n × F). Here, M = 59, n = 2 (Co²⁺), F = 96500, I = 10 A, and t = 109 × 60 seconds. Substituting values, m = (59 / (2 × 96500)) × 10 × 109 × 60 = 4.0 g.

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