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Molar conductivities (Λ°m) at infinite dilution of NaCl, HCl and CH3COONa are 126.4, 425.9 and 91.0 S cm² mol⁻¹ respectively. Λ°m for CH3COOH will be:

1. 425.5 S cm² mol⁻¹
2. 180.5 S cm² mol⁻¹
3. 290.8 S cm² mol⁻¹
4. 390.5 S cm² mol⁻¹

Correct answer: 180.5 S cm² mol⁻¹

Solution

Using Kohlrausch's Law of independent migration of ions, Λ°m(CH3COOH) = Λ°m(HCl) + Λ°m(CH3COONa) - Λ°m(NaCl) = 425.9 + 91.0 - 126.4 = 390.5 S cm² mol⁻¹.

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