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Following limiting molar conductivities are given as: λ°m(H2SO4) = x S cm² mol⁻¹ λ°m(K2SO4) = y S cm² mol⁻¹ λ°m(CH3COOK) = z S cm² mol⁻¹ λ°m (in S cm² mol⁻¹) for CH3COOH will be

1. (a) (x − y) / 2 + z
2. (b) x − y + 2z
3. (c) x + y + z
4. (d) x − y + z

Correct answer: (a) (x − y) / 2 + z

Solution

The limiting molar conductivity of CH3COOH can be calculated using the principle of Kohlrausch's Law of independent migration of ions. By subtracting the contribution of K+ ions (from K2SO4) and adding the contribution of CH3COO− ions (from CH3COOK), the correct formula is (x − y) / 2 + z.

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