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Which of the following species has the same bond order equal to 3?

1. CN⁻: no. of electrons = 6 + 7 + 1 = 14, bond order = 3
2. CO: no. of electrons = 6 + 8 = 14, bond order = 3
3. NO⁺: no. of electrons = 7 + 8 - 1 = 14, bond order = 3
4. O₂⁻: no. of electrons = 8 + 8 + 1 = 17, bond order = 3

Correct answer: CN⁻: no. of electrons = 6 + 7 + 1 = 14, bond order = 3

Solution

The bond order of CN⁻, CO, and NO⁺ is indeed 3, but O₂⁻ has a bond order of 1.5 due to its 17 electrons. Thus, CN⁻ is correct as it has a bond order of 3.

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