Exams › NEET › Chemistry

Among LiCl, BeCl2, BCl3 and CCl4, the covalent bond character follows the order

1. LiCl < BeCl2 > BCl3 > CCl4
2. BeCl2 < BCl3 < CCl4 < LiCl
3. LiCl < BeCl2 < BCl3 < CCl4
4. LiCl > BeCl2 > BCl3 > CCl4

Correct answer: LiCl < BeCl2 < BCl3 < CCl4

Solution

The covalent character increases with the polarization of the bond, which depends on the cation's charge density and the anion's polarizability. As we move from LiCl to CCl4, the covalent character increases due to decreasing ionic character.

Related NEET Chemistry questions

• Which of the following have identical bond order? (I) \( \boldsymbol{C} \boldsymbol{N}^{-} \) (II) \( \boldsymbol{O}_{\mathbf{2}}^{-} \) \( (\|\|) N O^{+} \) \( (\mid V) C N^{+} \)
• What type of bond does \( M g \) form with \( C l ? \)
• Shape of \( C O_{2} \) is:
• The shape of \( s p^{3} d^{2} \) hybridized molecule with 2 lone pairs will be:
• The hybrid orbitals with \( 33.33 \% \) Scharacter are involved in the bonding of one of the crystalline allotropes of carbon. The allotrope is :
• In certain polar solvents \( \boldsymbol{P} \boldsymbol{C l}_{5} \) undergoes an ionisation reaction in which \( C l^{-} \) ion leaves one \( P C l_{5} \) molecule and attaches itself to another \( 2 P C l_{5} \rightleftharpoons P C l_{4}^{+}+P C l_{6}^{-} \) What are the changes in the geometrical shapes that occur in this ionisation?

⚔️ Practice NEET Chemistry free + battle 1v1 →