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The empirical formula of a compound with the following composition is: C = 38.71%, H = 9.67%, O = 51.62%.

1. CH3O
2. CH2O
3. C2H4O2
4. CH3OH

Correct answer: CH2O

Solution

To find the empirical formula, divide the percentage composition of each element by its molar mass: C (38.71/12), H (9.67/1), O (51.62/16). Simplify the resulting mole ratios to the smallest whole numbers, yielding CH2O.

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