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The number of atoms in 22400 cc of N2O gas at STP is:
- 6.02 × 10^23
- 1.8 × 10^22
- 3 × 6.02 × 10^23
- 1.32 × 10^23
Correct answer: 3 × 6.02 × 10^23
Solution
At STP, 22400 cc (or 22.4 L) of any gas corresponds to 1 mole. N2O has 3 atoms per molecule, so 1 mole of N2O contains 3 × 6.02 × 10^23 atoms.
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