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Volume occupied by 1 gram of water is:

1. 6.023 × 10^23 molecules of water = 1 cm^3
2. Volume occupied by 6.023 × 10^23 molecules of water = 1 cm^3
3. 1 g water = 1/18 [moles of water]
4. Volume occupied by 1 mole of water = 18 cm^3

Correct answer: Volume occupied by 6.023 × 10^23 molecules of water = 1 cm^3

Solution

1 gram of water corresponds to 1 cm³ because the density of water is 1 g/cm³. This means 6.023 × 10^23 molecules (1 mole) of water occupy 18 cm³, and 1 gram (1/18 mole) occupies 1 cm³.

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