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How many moles of lead (II) chloride will be formed from a reaction between 6.5 g of PbO and 3.2 g of HCl?

1. 0.044
2. 0.333
3. 0.011
4. 0.029

Correct answer: 0.044

Solution

The reaction is PbO + 2HCl → PbCl2 + H2O. Moles of PbO = 6.5/223.2 = 0.029. Moles of HCl = 3.2/36.5 = 0.087. Since 1 mole of PbO reacts with 2 moles of HCl, PbO is the limiting reagent. Thus, moles of PbCl2 formed = moles of PbO = 0.029.

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