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10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount of water produced in this reaction will be:
- 3 mol
- 4 mol
- 1 mol
- 2 mol
Correct answer: 4 mol
Solution
The reaction is 2H2 + O2 → 2H2O. Moles of H2 = 10/2 = 5 mol, and moles of O2 = 64/32 = 2 mol. O2 is the limiting reagent, producing 2 × 2 = 4 mol of H2O.
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