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In an experiment it showed that 10 mL of 0.05 M solution of chloride required 10 mL of 0.1 M solution of AgNO3. Which of the following will be the formula of the chloride (X stands for the symbol of the element other than chlorine)?

1. X2Cl
2. X2Cl2
3. XCl2
4. XCl4

Correct answer: XCl2

Solution

The reaction between chloride and AgNO3 is a precipitation reaction forming AgCl. The stoichiometry shows that 1 mole of chloride reacts with 1 mole of AgNO3. Since 10 mL of 0.05 M chloride reacts with 10 mL of 0.1 M AgNO3, the chloride must have 2 Cl atoms per formula unit, making the formula XCl2.

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