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Volume occupied by one molecule of water (density = 1 g cm^-3) is:

1. 9.0 × 10^-23 cm^3
2. 6.023 × 10^-23 cm^3
3. 3.0 × 10^-23 cm^3
4. 5.5 × 10^-23 cm^3

Correct answer: 9.0 × 10^-23 cm^3

Solution

The molar mass of water is 18 g/mol, and its density is 1 g/cm³. Using Avogadro's number (6.022 × 10^23 molecules/mol), the volume of one molecule is calculated as (18 g / 1 g/cm³) ÷ 6.022 × 10^23, which equals 9.0 × 10^-23 cm³.

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