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What volume of oxygen gas (O2) measured at 0°C and 1 atm, is needed to burn completely 11.2 L of propane gas (C3H8) measured under the same conditions?

1. 7L
2. 6L
3. 5L
4. 10L

Correct answer: 10L

Solution

The combustion reaction of propane is C3H8 + 5O2 → 3CO2 + 4H2O. From the stoichiometry, 1 mole of propane reacts with 5 moles of oxygen. Since gases at the same conditions have volumes proportional to moles, 11.2 L of propane will require 11.2 × 5 = 56 L of oxygen.

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