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The number of atoms in 0.1 mol of a triatomic gas is: (NA = 6.02 × 10^23 mol^-1)
- 6.026 × 10^22
- 1.806 × 10^23
- 3.600 × 10^23
- 1.800 × 10^22
Correct answer: 3.600 × 10^23
Solution
A triatomic gas contains 3 atoms per molecule. The total number of molecules in 0.1 mol is 0.1 × NA. Multiplying this by 3 gives the total number of atoms: 0.1 × 6.02 × 10^23 × 3 = 1.806 × 10^23.
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