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JEE Main Chemistry: Hydrogen questions with solutions

70 questions with worked solutions.

Questions

Q1. When potassium fluoride reacts with hydrofluoric acid to give KHF₂, which ionic species are present in the compound?

  1. K⁺, F⁻ and H⁺
  2. K⁺, F⁻ and HF
  3. K⁺ and [HF₂]⁻
  4. [KHF]⁺ and F₂

Answer: K⁺ and [HF₂]⁻

In the compound KHF₂, potassium (K⁺) acts as a cation while the anion is the bifluoride ion ([HF₂]⁻), which is formed from the interaction of hydrofluoric acid and fluoride ions, thus making option C the correct choice.

Q2. In the sequence below, determine the species represented by x and y: 2H2SO4(aq) —electrolysis→ x —hydrolysis→ y + 2H+(aq) + H2O2(aq)

  1. x = H2SO4(aq), y = 2H2SO4(aq)
  2. x = H2SO3SO3H(aq), y = 2H2SO3(aq)
  3. x = H2SO3SO3H(aq), y = H2SO4(aq)
  4. x = H2SO4(aq), y = H2SO3SO3H(aq)

Answer: x = H2SO3SO3H(aq), y = H2SO4(aq)

The correct option indicates that during the electrolysis of sulfuric acid (H2SO4), it is converted into a different species (H2SO3SO3H), which upon hydrolysis yields sulfuric acid (H2SO4) and other products. This reflects the chemical transformations occurring in the sequence.

Q3. Which of the following methods can produce hydrogen of very high purity (99.9%)?

  1. Passing methane over steam
  2. Blending natural hydrocarbons with large molecular mass
  3. Electrolyzing water
  4. Treating hydride salts with water

Answer: Electrolyzing water

Electrolyzing water separates hydrogen and oxygen through an electrical current, resulting in hydrogen that is highly pure, typically reaching purities of 99.9% or higher.

Q4. An inorganic substance evolves oxygen on heating, makes an acidic potassium iodide solution turn violet, and decolourises acidified potassium permanganate. Which substance is it?

  1. SO3
  2. KNO3
  3. H2O2
  4. All of the above

Answer: H2O2

H2O2, or hydrogen peroxide, decomposes upon heating to release oxygen, reacts with potassium iodide to form iodine which turns the solution violet, and reduces potassium permanganate, leading to its decolorization.

Q5. Identify the incorrect statement about ortho and para hydrogen.

  1. Normal hydrogen is an equilibrium blend of ortho-hydrogen and para-hydrogen.
  2. In ortho-hydrogen, the spins of the two nuclei are aligned in the same direction.
  3. Ortho and para hydrogen differ in their chemical properties.
  4. In para-hydrogen, the spins of the two nuclei are oriented in opposite directions.

Answer: Ortho and para hydrogen differ in their chemical properties.

Ortho- and para-hydrogen have identical chemical properties and differ only in physical properties (boiling point, thermal conductivity), so 'they differ in chemical properties' (option 2) is the incorrect statement. The stored statement (normal H2 is an ortho/para blend) is true.

Q6. With reference to hydrogen peroxide (H₂O₂), identify the statement that is not true:

  1. It should be kept in plastic containers or in glass bottles lined with wax and stored away from light.
  2. It must be protected from dust contamination.
  3. It functions only as an oxidising agent.
  4. It breaks down when exposed to light.

Answer: It functions only as an oxidising agent.

Hydrogen peroxide is versatile and can act as both an oxidizing and a reducing agent, depending on the reaction conditions, making the statement incorrect.

Q7. In the reaction below, determine x and y, and name the resulting gas mixture: CH₄(g) + H₂O(g) —1270 K, Ni→ x + y

  1. x = CO₂, y = H₂O; water gas
  2. x = CO, y = H₂; syngas
  3. x = CO, y = H₂O; syngas
  4. x = CO₂, y = H₂; syngas

Answer: x = CO, y = H₂; syngas

The reaction involves methane and steam at high temperature, which typically produces carbon monoxide and hydrogen gas, known as syngas. This is a common process in gasification, where methane reacts with water to yield these two products.

Q8. Which of the following statements about helium is not correct?

  1. It is used to create and maintain strong superconducting magnets.
  2. It serves as a cryogenic medium for experiments conducted at very low temperatures.
  3. It is used to inflate balloons in place of hydrogen because it is lighter and does not catch fire.
  4. It is employed in gas-cooled nuclear reactors.

Answer: It is used to inflate balloons in place of hydrogen because it is lighter and does not catch fire.

Helium is denser (heavier) than hydrogen, not lighter; it is used in balloons because it is non-flammable, not because it is lighter. The other statements about superconducting magnets, cryogenics, and gas-cooled reactors are correct.

Q9. Which of the following hydrogen bonds is strongest?

  1. O−H···F
  2. O−H···H
  3. F−H···F
  4. O−H···O

Answer: F−H···F

Fluorine is the most electronegative element, so the F-H...F hydrogen bond is the strongest of the listed options.

Q10. Which of the following could act as a propellant for rockets?

  1. Liquid oxygen + liquid argon
  2. Liquid hydrogen + liquid oxygen
  3. Liquid nitrogen + liquid oxygen
  4. Liquid hydrogen + liquid nitrogen

Answer: Liquid hydrogen + liquid oxygen

Liquid hydrogen and liquid oxygen are commonly used as rocket propellants because they undergo a highly efficient combustion reaction, producing a large amount of thrust and water vapor as the only byproduct, making them both powerful and environmentally friendly.

Q11. From the following statements regarding H2O2, choose the incorrect statement: (1) It can act only as an oxidizing agent (2) It decomposes on exposure to light (3) It has to be stored in plastic or wax lined glass bottles in dark (4) It has to be kept away from dust

  1. It can act only as an oxidizing agent
  2. It decomposes on exposure to light
  3. It has to be stored in plastic or wax lined glass bottles in dark
  4. It has to be kept away from dust

Answer: It can act only as an oxidizing agent

Hydrogen peroxide (H2O2) can act as both an oxidizing agent and a reducing agent, making the statement that it can act only as an oxidizing agent incorrect.

Q12. Which one of the following statements about water is FALSE ? (1) Water is oxidized to oxygen during photosynthesis (2) Water can act both as an acid and as a base (3) There is extensive intramolecular hydrogen bonding in the condensed phase (4) Ice formed by heavy water sinks in normal water

  1. Water is oxidized to oxygen during photosynthesis
  2. Water can act both as an acid and as a base
  3. There is extensive intramolecular hydrogen bonding in the condensed phase
  4. Ice formed by heavy water sinks in normal water

Answer: There is extensive intramolecular hydrogen bonding in the condensed phase

The statement about extensive intramolecular hydrogen bonding in the condensed phase is incorrect because water primarily exhibits intermolecular hydrogen bonding, which is crucial for its unique properties, rather than significant intramolecular bonding.

Q13. The strength of 11.2 volume solution of H2O2 is: [Given that molar mass of H = 1 g mol⁻¹ and O = 16 g mol⁻¹]

  1. 1.7%
  2. 34%
  3. 3.4%
  4. 13.6%

Answer: 3.4%

Volume strength 11.2 means molarity = 11.2/11.2 = 1 M. Strength = 1 * 34 = 34 g/L, i.e. 34 g per 1000 g (~1 L) solution = 3.4% w/v.

Q14. The correct statements among (a) to (d) are: (a) saline hydrides produce H2 gas when reacted with H2O. (b) reaction of LiAlH4 with BF3 leads to B2H6. (c) PH3 and CH4 are electron - rich and electron - precise hydrides, respectively. (d) HF and CH4 are called as molecular hydrides. (1) (a), (b), (c) and (d) (2) (a), (c) and (d) only (3) (c) and (d) only (4) (a), (b) and (c) only

  1. (a), (b), (c) and (d)
  2. (a), (c) and (d) only
  3. (c) and (d) only
  4. (a), (b) and (c) only

Answer: (a), (b), (c) and (d)

(a) Saline (ionic) hydrides like NaH react with water to give H2. (b) 4BF3 + 3LiAlH4 -> 2B2H6 + 3LiF + 3AlF3. (c) PH3 has a lone pair (electron-rich); CH4 has exactly enough electrons (electron-precise). (d) HF and CH4 are molecular hydrides. All four are correct.

Q15. The correct statements among (a) to (d) regarding H2 as a fuel are: (a) It produces less pollutants than petrol. (b) A cylinder of compressed dihydrogen weighs ~ 30 times more than a petrol tank producing the same amount of energy. (c) Dihydrogen is stored in tanks of metal alloys like NaNi5. (d) On combustion, values of energy released per gram of liquid dihydrogen and LPG are 50 and 142 kJ, respectively.

  1. (a) and (c) only
  2. (b) and (d) only
  3. (a), (b) and (c) only
  4. (b), (c) and (d) only

Answer: (a), (b) and (c) only

(a) H2 burns cleaner, (b) a compressed-H2 cylinder weighs ~30x a petrol tank for equal energy, and (c) H2 is stored in alloys like NaNi5 -- all true. (d) is false because the energy per gram values for liquid H2 (~142 kJ) and LPG (~50 kJ) are swapped. Correct set: (a),(b),(c).

Q16. The equation that represents the water-gas shift reaction is:

  1. CO(g) + H2O(g) 673K Catalyst CO2(g) + H2(g)
  2. CH4(g) + H2O(g) 1270K Ni CO(g) + 3 H2(g)
  3. C(s) + H2O(g) 1270K CO(g) + H2(g)
  4. 2C(s) + O2(g) + 4N2(g) 1273K 2CO(g) + 4N2(g)

Answer: CO(g) + H2O(g) 673K Catalyst CO2(g) + H2(g)

The correct option accurately represents the water-gas shift reaction, where carbon monoxide reacts with water vapor to produce carbon dioxide and hydrogen gas, typically at elevated temperatures and in the presence of a catalyst.

Q17. Among statement (a) – (d), the correct ones are: (a) Decomposition of hydrogen peroxide gives dioxygen. (b) Like hydrogen peroxide, compound, such as KClO3, Pb(NO3)2 and NaNO3 when heated liberate dioxygen. (c) 2-Ethylanthraquinone is useful for the industrial preparation of hydrogen peroxide. (d) Hydrogen peroxide is used for the manufacture of sodium perborate.

  1. (1) (a), (c) and (d) only
  2. (2) (a), (b), (c) and (d)
  3. (3) (a) and (c) only
  4. (4) (a), (b) and (c) only

Answer: (2) (a), (b), (c) and (d)

All four statements are accurate: hydrogen peroxide decomposes to release dioxygen, compounds like KClO3 and others can also liberate dioxygen upon heating, 2-Ethylanthraquinone is indeed used in the industrial synthesis of hydrogen peroxide, and hydrogen peroxide is utilized in the production of sodium perborate.

Q18. Hydrogen has three isotopes (A), (B) and (C). If the number of neutron(s) in (A), (B) and (C) respectively, are (x), (y) and (z), the sum of (x), (y) and (z) is:

  1. 4
  2. 3
  3. 2
  4. 1

Answer: 3

Hydrogen's three isotopes have 0 (protium), 1 (deuterium) and 2 (tritium) neutrons. Their sum is 0 + 1 + 2 = 3.

Q19. The correct statements about H2O2 are: (A) used in the treatment of effluents. (B) used as both oxidising and reducing agents. (C) the two hydroxyl groups lie in the same plane. (D) miscible with water. Choose the correct answer from the options given below:

  1. (A), (B), (C) and (D)
  2. (A), (B) and (D) only
  3. (B), (C) and (D) only
  4. (A), (C) and (D) only

Answer: (A), (B) and (D) only

Options (A), (B), and (D) are correct because hydrogen peroxide (H2O2) is indeed used in effluent treatment, can act as both an oxidizing and reducing agent, and is miscible with water. However, option (C) is incorrect as the two hydroxyl groups in H2O2 are not in the same plane due to the molecule's non-planar structure.

Q20. Given below are two statements: One is labelled as Assertion A and other is labelled as Reason R. Assertion A: The dihedral angles in H2O2 in gaseous phase is 90.2° and in solid phase is 111.5°. Reason R: The change in dihedral angle in solid and gaseous phase is due to the difference in the intermolecular forces. Choose the most appropriate answer from the options given below for A and R.

  1. A is correct but R is not correct.
  2. Both A and R are correct but R is not the correct explanation of A.
  3. Both A and R are correct and R is the correct explanation of A.
  4. A is not correct but R is correct.

Answer: Both A and R are correct and R is the correct explanation of A.

The dihedral angle of H2O2 is 90.2 deg in the gas phase and 111.5 deg in the solid phase; both values are standard. The phase-dependent change arises because intermolecular forces (notably H-bonding in the solid) differ between phases, so R correctly explains A. Both A and R are correct and R IS the correct explanation.

Q21. Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: Hydrogen is the most abundant element in the Universe, but it is not the most abundant gas in the troposphere. Reason R: Hydrogen is the lightest element. In the light of the above statements, choose the correct answer from the options given below:

  1. A is true but R is false
  2. Both A and R are true and R is the correct explanation of A
  3. A is false but R is true
  4. Both A and R are true but R is NOT the correct explanation of A

Answer: Both A and R are true and R is the correct explanation of A

The assertion is correct as hydrogen is indeed the most abundant element in the universe, while in the troposphere, nitrogen and oxygen are more prevalent gases. The reason is also true since hydrogen's lightness contributes to its tendency to rise and escape the troposphere, explaining why it is not the most abundant gas there.

Q22. The correct statement about B2H6 is: (1) Terminal B–H bonds have less p-character when compared to bridging bonds. (2) The two B–H–B bonds are not of same length. (3) All B–H–B angles are of 120° (4) Its fragment, BH3, behaves as a Lewis base

  1. (1)
  2. (2)
  3. (3)
  4. (4)

Answer: (1)

Terminal B–H bonds in B2H6 have a higher p-character compared to bridging bonds due to their different bonding environments; terminal bonds are more localized while bridging bonds involve more orbital overlap, leading to a difference in hybridization.

Q23. Water does not produce CO on reacting with:

  1. CO2
  2. C
  3. CH4
  4. C3H8

Answer: CO2

C, CH4 and C3H8 all react with steam to give CO (water-gas / steam reforming). CO2 with water does not produce CO, so the correct option is CO2.

Q24. The number of non-ionisable hydrogen atoms present in the final product obtained from the hydrolysis of PCl5 is: (1) 0 (2) 2 (3) 4 (4) 3

  1. 0
  2. 2
  3. 4
  4. 3

Answer: 0

PCl5 + 4H2O -> H3PO4 + 5HCl. In H3PO4 = (HO)3P=O there is no P-H bond; all three H atoms are on -OH groups and are ionizable, so the number of non-ionizable H atoms is 0.

Q25. Which of the following forms of hydrogen emits low energy β particles? (1) Deuterium ²H (2) Tritium ³H (3) Protium ¹H (4) Proton H⁺

  1. Deuterium ²H
  2. Tritium ³H
  3. Protium ¹H
  4. Proton H⁺

Answer: Tritium ³H

Tritium (³H) is a radioactive isotope of hydrogen that undergoes beta decay, emitting low energy beta particles, while deuterium and protium are stable isotopes and do not emit beta particles.

Q26. Deuterium resembles hydrogen in properties but:

  1. reacts slower than hydrogen
  2. reacts vigorously than hydrogen
  3. reacts just as hydrogen
  4. emits β+ particles

Answer: reacts slower than hydrogen

Deuterium, being an isotope of hydrogen with an additional neutron, has a greater mass which affects its reaction kinetics, causing it to react more slowly than regular hydrogen in chemical reactions.

Q27. Which one of the following statements is incorrect ? (1) Atomic hydrogen is produced when H2 molecules at a high temperature are irradiated with UV radiation. (2) At around 2000 K, the dissociation of dihydrogen into its atoms is nearly 8.1%. (3) Bond dissociation enthalpy of H2 is highest among diatomic gaseous molecules which contain a single bond. (4) Dihydrogen is produced on reacting zinc with HCl as well as NaOH(aq).

  1. Atomic hydrogen is produced when H2 molecules at a high temperature are irradiated with UV radiation.
  2. At around 2000 K, the dissociation of dihydrogen into its atoms is nearly 8.1%.
  3. Bond dissociation enthalpy of H2 is highest among diatomic gaseous molecules which contain a single bond.
  4. Dihydrogen is produced on reacting zinc with HCl as well as NaOH(aq).

Answer: At around 2000 K, the dissociation of dihydrogen into its atoms is nearly 8.1%.

The incorrect statement is (2): at about 2000 K the degree of dissociation of dihydrogen into atoms is only ~0.081%, not 8.1%. The other three statements (UV/arc gives atomic H; H2 has the highest single-bond dissociation enthalpy; Zn reacts with both HCl and NaOH to give H2) are all correct.

Q28. The highest industrial consumption of molecular hydrogen is to produce compounds of element:

  1. (1) Carbon
  2. (2) Nitrogen
  3. (3) Oxygen
  4. (4) Chlorine

Answer: (2) Nitrogen

Molecular hydrogen is primarily used in the Haber process to synthesize ammonia from nitrogen, which is essential for producing fertilizers and other nitrogen-containing compounds, making nitrogen the element with the highest industrial consumption of hydrogen.

Q29. Which of the following can be used to prevent the decomposition of H2O2 ?

  1. (1) Urea
  2. (2) Formaldehyde
  3. (3) Formic acid
  4. (4) Ethanol

Answer: (1) Urea

Hydrogen peroxide is stabilized against decomposition by adding small amounts of stabilizers such as urea (also glycerol, acetanilide, sodium stannate/pyrophosphate). Among the options, urea is the correct stabilizer.

Q30. The correct order of increasing intermolecular hydrogen bond strength is

  1. HCN < H2O < NH3
  2. HCN < CH4 < NH3
  3. CH4 < HCN < NH3
  4. CH4 < NH3 < HCN

Answer: CH4 < HCN < NH3

Hydrogen bonds are strongest in molecules where hydrogen is bonded to highly electronegative atoms like nitrogen. In this case, CH4 has no hydrogen bonding capability, HCN has moderate hydrogen bonding due to the presence of nitrogen, and NH3 has the strongest hydrogen bonds because of its ability to form multiple hydrogen bonds with surrounding molecules.

Q31. Dihydrogen reacts with CuO to give

  1. CuH2
  2. Cu
  3. Cu2O
  4. Cu(OH)2

Answer: Cu

Dihydrogen reacts with copper(II) oxide (CuO) through a reduction process, where hydrogen reduces CuO to elemental copper (Cu) while itself being oxidized to water.

Q32. Hydrogen has three isotopes: protium (¹H), deuterium (²H or D) and tritium (³H or T). They have nearly same chemical properties but different physical properties. They differ in (1) Number of protons (2) Atomic number (3) Electronic configuration (4) Atomic mass

  1. Number of protons
  2. Atomic number
  3. Electronic configuration
  4. Atomic mass

Answer: Atomic mass

The isotopes of hydrogen differ in atomic mass because they have varying numbers of neutrons, which affects their overall mass while maintaining the same number of protons and electrons.

Q33. Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R Assertion A: Hydrogen is an environment friendly fuel. Reason R: Atomic number of hydrogen is 1 and it is very light element. In the light of the above statements, choose the correct answer from the options given below (1) Both A and R are true and R is the correct explanation of A. (2) A is true but R is false (3) Both A and R are true but R is NOT the correct explanation of A. (4) A is false but R is true

  1. Both A and R are true and R is the correct explanation of A.
  2. A is true but R is false
  3. Both A and R are true but R is NOT the correct explanation of A.
  4. A is false but R is true

Answer: Both A and R are true but R is NOT the correct explanation of A.

Hydrogen is indeed considered an environmentally friendly fuel because it produces only water when burned, making it a clean energy source. However, the atomic number and lightness of hydrogen do not directly explain its environmental benefits, which is why the reason provided does not serve as a correct explanation for the assertion.

Q34. O–O bond length in H2O2 is X than the O–O bond length in F2O2. The O–H bond length in H2O2 is Y than that of the O–F bond in F2O2. Choose the correct option for X and Y from those given below

  1. X-shorter, Y-Shorter
  2. X-shorter, Y-longer
  3. X-longer, Y-Shorter
  4. X-longer, Y-longer

Answer: X-longer, Y-Shorter

The O–O bond in H2O2 is longer than in F2O2 due to the presence of steric hindrance and electron repulsion from the larger fluorine atoms, which shortens the O–F bond. Additionally, the O–H bond in H2O2 is shorter than the O–F bond in F2O2 because the electronegativity of fluorine pulls electron density away, resulting in a longer bond.

Q35. Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: Physical properties of isotopes of hydrogen are different. Reason R: Mass difference between isotopes of hydrogen is very large. In the light of the above statements, choose the correct answer from the options given below:

  1. Both A and R are true and R is the correct explanation of A
  2. A is false but R is true
  3. A is true but R is false
  4. Both A and R are true but R is NOT the correct explanation of A

Answer: Both A and R are true and R is the correct explanation of A

The assertion is correct because isotopes of hydrogen, such as protium, deuterium, and tritium, exhibit different physical properties due to their varying masses. The reason is also true, as the significant mass difference between these isotopes leads to observable variations in their physical properties, making it a valid explanation for the assertion.

Q36. Given below are two statements: Statement-I: Methane and steam passed over a heated Ni catalyst produces hydrogen gas. Statement-II: Sodium nitrite reacts with NH4Cl to give H2O, N2 and NaCl. In the light of the above statements, choose the most appropriate answer from the options given below:

  1. Statement I is incorrect but Statement II is correct
  2. Both the statements I and II are incorrect
  3. Statement I is correct but Statement II is incorrect
  4. Both the statements I and II are correct

Answer: Both the statements I and II are correct

Both statements are accurate; Statement I describes the steam reforming process where methane reacts with steam over a nickel catalyst to produce hydrogen, while Statement II correctly outlines the reaction between sodium nitrite and ammonium chloride, resulting in water, nitrogen gas, and sodium chloride.

Q37. Which hydride among the following is less stable ?

  1. BeH2
  2. HF
  3. NH3
  4. LiH

Answer: BeH2

BeH2 is less stable because it has a unique polymeric structure that leads to weaker bonding interactions compared to the other hydrides listed, making it more reactive and less stable under standard conditions.

Q38. Match List I with List II. List I (Type of Hydride) A. Electron deficient hydride B. Electron rich hydride C. Electron precise hydride D. Saline hydride List II (Example) I. MgH2 II. HF III. B2H6 IV. CH4 Choose the correct answer from the options given below:

  1. A-III, B-II, C-IV, D-I
  2. A-II, B-III, C-I, D-IV
  3. A-II, B-III, C-IV, D-I
  4. A-III, B-II, C-I, D-IV

Answer: A-III, B-II, C-IV, D-I

The correct matches reflect the characteristics of each type of hydride: B2H6 is an electron deficient hydride due to its lack of sufficient electrons for bonding; HF is an electron rich hydride as it has a strong electronegative atom; CH4 is an electron precise hydride with a balanced electron count; and MgH2 is a saline hydride, which typically forms ionic bonds.

Q39. ’25 volume’ hydrogen peroxide means

  1. 1 L marketed solution contains 250 g of H2O2.
  2. 100 mL marketed solution contains 25 g of H2O2.
  3. 1 L marketed solution contains 25 g of H2O2.
  4. 1 L marketed solution contains 75 g of H2O2.

Answer: 1 L marketed solution contains 75 g of H2O2.

The term '25 volume' hydrogen peroxide indicates that 1 liter of the solution can release 25 liters of oxygen gas at standard conditions, which corresponds to a concentration of approximately 75 grams of H2O2 per liter.

Q40. Lithium aluminium hydride can be prepared from the reaction of

  1. LiH and Al(OH)3
  2. LiCl and Al2H6
  3. LiCl, Al and H2
  4. LiH and Al2Cl6

Answer: LiH and Al2Cl6

Lithium aluminium hydride is synthesized through the reaction of lithium hydride with aluminium chloride, where lithium donates its hydride ions to aluminium, resulting in the formation of the desired compound.

Q41. Given below are two statements: one is labeled as Assertion (A) and the other is labeled as Reason (R). Assertion (A): PH3 has lower boiling point than NH3. Reason (R): In liquid state NH3 molecules are associated through van der Waals' forces, but PH3 molecules are associated through hydrogen bonding. In the light of above statements, choose the most appropriate answer from the options given below. (1) Both (A) and (R) are correct and (R) is the correct explanation of (A). (2) Both (A) and (R) are correct but (R) is not the correct explanation of (A). (3) (A) is correct but (R) is not correct. (4) (A) is not correct but (R) is correct.

  1. Both (A) and (R) are correct and (R) is the correct explanation of (A).
  2. Both (A) and (R) are correct but (R) is not the correct explanation of (A).
  3. (A) is correct but (R) is not correct.
  4. (A) is not correct but (R) is correct.

Answer: (A) is correct but (R) is not correct.

PH3 has a lower boiling point than NH3 due to weaker van der Waals forces in PH3 compared to the strong hydrogen bonding in NH3, making the assertion true. However, the reason provided incorrectly states that PH3 is associated through hydrogen bonding, which is not the case, thus making the reason incorrect.

Q42. On passing a gas, ‘X’, through Nessler’s reagent, a brown precipitate is obtained. The gas ‘X’ is

  1. Cl2
  2. NH3
  3. H2S
  4. CO2

Answer: NH3

Nessler's reagent is specifically used to detect ammonia (NH3) in a solution, producing a brown precipitate when ammonia is present. This reaction is characteristic of ammonia, distinguishing it from the other gases listed.

Q43. The correct statement/s about Hydrogen bonding is/are: A. Hydrogen bonding exists when H is covalently bonded to the highly electro negative atom. B. Intermolecular H bonding is present in o-nitro phenol C. Intramolecular H bonding is present in HF. D. The magnitude of H bonding depends on the physical state of the compound. E. H-bonding has powerful effect on the structure and properties of compounds. Choose the correct answer from the options given below:

  1. (1) A only
  2. (2) A, D, E only
  3. (3) A, B, D only
  4. (4) A, B, C only

Answer: (2) A, D, E only

A, D, E are correct. B is false because o-nitrophenol shows INTRAmolecular H-bonding (the chelate ring), and C is false because HF exhibits INTERmolecular H-bonding, not intramolecular. So the right set is A, D, E only.

Q44. Given below are two statements: Statement I: The increasing order of boiling point of hydrogen halides is HCl < HBr < HI < HF. Statement II: The increasing order of melting point of hydrogen halides is HCl < HBr < HF < HI. In the light of the above statements, choose the correct answer from the options given below:

  1. (1) Both Statement I and Statement II are true
  2. (2) Statement I is true but Statement II is false
  3. (3) Both Statement I and Statement II are false
  4. (4) Statement I is false but Statement II is true

Answer: (1) Both Statement I and Statement II are true

Both statements accurately reflect the trends in boiling and melting points of hydrogen halides. The boiling points increase due to the strength of hydrogen bonding and molecular weight, while the melting points are influenced by molecular structure and intermolecular forces.

Q45. Which of the following could act as propellant for rockets?

  1. Liquid oxygen + liquid argon
  2. Liquid hydrogen + liquid oxygen
  3. Liquid nitrogen + liquid oxygen
  4. Liquid hydrogen + liquid nitrogen

Answer: Liquid hydrogen + liquid oxygen

Liquid hydrogen and liquid oxygen are commonly used as rocket propellants because they combine to produce a high-energy reaction, resulting in significant thrust and efficiency, making them ideal for space travel.

Q46. Hydrogen bomb is based on the principle of

  1. Nuclear fission
  2. Natural radioactivity
  3. Nuclear fusion
  4. Artificial radioactivity

Answer: Nuclear fusion

A hydrogen bomb releases energy by the fusion of light nuclei (hydrogen isotopes) into heavier ones. The stored answer 'nuclear fission' is wrong; the correct principle is nuclear fusion.

Q47. The correct order of the thermal stability of hydrogen halides (H − X) is

  1. HI > HBr > HCl > HF
  2. HF > HCl > HBr > HI
  3. HCl < HF > HBr < HI
  4. HI > HCl < HF < HBr

Answer: HF > HCl > HBr > HI

Thermal stability of hydrogen halides decreases down the group as bond strength weakens: HF>HCl>HBr>HI, option index 1, not the stored reverse order.

Q48. Which of the following hydrogen bonds is the strongest?

  1. O – H......F
  2. F – H......F
  3. O – H......O
  4. O – H......F

Answer: F – H......F

Hydrogen-bond strength rises with the electronegativity of the atoms involved, and fluorine is the most electronegative element. Therefore F-H...F is the strongest hydrogen bond, stronger than any O-H...O or O-H...F bond.

Q49. Regarding the industrial manufacture of hydrogen from water gas (a mixture of CO and H2), which statement is correct?

  1. CO and H2 are separated fractionally on the basis of their density difference
  2. CO is eliminated by absorption in aqueous cuprous chloride solution
  3. H2 is removed by occlusion in palladium
  4. CO is first converted to CO2 by reaction with steam in the presence of a catalyst, and the CO2 is then absorbed in alkali

Answer: CO is first converted to CO2 by reaction with steam in the presence of a catalyst, and the CO2 is then absorbed in alkali

This option is correct because it describes the water-gas shift reaction, where carbon monoxide reacts with steam to produce carbon dioxide and hydrogen. The subsequent absorption of CO2 in alkali effectively removes it from the gas mixture, allowing for the purification of hydrogen.

Q50. The numbers of protons, electrons and neutrons in a molecule of heavy water are respectively:

  1. 8, 10, 11
  2. 10, 10, 10
  3. 10, 11, 10
  4. 11, 10, 10

Answer: 10, 10, 10

D2O: two deuterium atoms give 2 protons, 2 neutrons, 2 electrons; oxygen-16 gives 8 protons, 8 neutrons, 8 electrons. Totals are 10 protons, 10 electrons, 10 neutrons.

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