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The number of non-ionisable hydrogen atoms present in the final product obtained from the hydrolysis of PCl5 is: (1) 0 (2) 2 (3) 4 (4) 3

1. 0
2. 2
3. 4
4. 3

Correct answer: 0

Solution

PCl5 + 4H2O -> H3PO4 + 5HCl. In H3PO4 = (HO)3P=O there is no P-H bond; all three H atoms are on -OH groups and are ionizable, so the number of non-ionizable H atoms is 0.

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