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Hydrogen has three isotopes (A), (B) and (C). If the number of neutron(s) in (A), (B) and (C) respectively, are (x), (y) and (z), the sum of (x), (y) and (z) is:
- 4
- 3
- 2
- 1
Correct answer: 3
Solution
Hydrogen's three isotopes have 0 (protium), 1 (deuterium) and 2 (tritium) neutrons. Their sum is 0 + 1 + 2 = 3.
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