Exams › JEE Advanced › Maths
Given P(A) = 3/4, P(A intersection B intersection C complement) = 1/3, and P(A intersection B complement intersection C complement) = 1/3. Find P(A intersection C).
- 1/6
- 1/15
- 1/12
- 1/9
Correct answer: 1/12
Solution
P(A) = P(A*B*C) + P(A*B*C') + P(A*B'*C) + P(A*B'*C') = 3/4. Subtracting the two given terms: P(A*B*C) + P(A*B'*C) = 3/4 - 1/3 - 1/3 = 1/12. This sum equals P(A*C).
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