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Given that A represents the divisors of 15, B contains prime numbers less than 10, and C includes even numbers less than 9, how many elements are there in the intersection of (A ∪ C) and B?
- 1
- 2
- 3
- 4
Correct answer: 3
Solution
A (divisors of 15) = {1,3,5,15}, B (primes <10) = {2,3,5,7}, C (even <9) = {2,4,6,8}. A U C = {1,2,3,4,5,6,8,15}; intersecting with B gives {2,3,5}, which has 3 elements (index 2). The stored answer (1) is wrong.
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