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ExamsJEE AdvancedMaths

If set A contains 3 elements and set B contains 6 elements, what is the minimum number of elements in A union B?

  1. 3
  2. 6
  3. 9
  4. 18

Correct answer: 6

Solution

By inclusion-exclusion, |A union B| = |A| + |B| - |A intersect B|. This is minimized when the intersection is largest. Since |A|=3, the maximum intersection is 3 (A subset of B), giving |A union B| = 3 + 6 - 3 = 6.

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