Exams › IBPS PO › Reasoning › Logical Reasoning
152 questions with worked solutions.
Answer: Neither I nor II follows
The statement gives the number of runs scored by spinners, not the number of spinners in the team. So conclusion I does not follow. Nothing is said about who opened the batting, so conclusion II also does not follow.
Answer: Only conclusion I follows
The statement indicates that old things are replaced by new ones, which supports the idea that change is natural. However, it does not say that old ideas should be discarded merely because they are old.
Answer: Only conclusion II follows
The statement says population increase and depleting resources will be the scenario in many developing countries. This supports the inference that providing a decent quality of life will become difficult. But it does not say population will stop increasing, so conclusion I does not follow.
Answer: Neither I nor II follows
The statement only describes the rise in TV viewing and the decline in newspaper readership. It does not suggest any specific method to increase readership or any need to send experts abroad. Therefore, neither conclusion follows.
Answer: Both I and III are true
From N ≥ U > W and W ≥ S, we get N ≥ U > W ≥ S, so S < N and hence S < G because G = N. Also, H ≤ S and S ≤ W, so H < W is true. Conclusion II cannot be confirmed because F is only known to be less than H, not necessarily less than U.
Answer: None is true
The statements do not establish a definite relation between A and I, D and F, or F and I. Since each conclusion depends on missing direct comparison, none of them is definitely true.
Answer: Four
The clues force Q and V into Barcelona, while P and Z form another pair and O with L form a third group. Using the restrictions on N, W, and the odd-number condition for Barcelona, the only consistent distribution leaves four people in Texas. Hence, the answer is Four.
Answer: if neither conclusion I nor II follows.
From 'some triangles are rectangles,' we cannot conclude that some triangles are not rectangles. Also, 'all circles are triangles' and 'all rectangles are squares' do not imply that no square is a circle. Hence neither conclusion follows.
Answer: R
P is heavier than only three people, so P is 4th from the lightest. Q is heavier than P, and V is heavier than Q, while U and T are both heavier than R. From the given relations, R must be placed as the third lightest boy.
Answer: Unknown person
The arrangement constraints fix some positions, but not enough to uniquely determine H's immediate right neighbour. Since multiple valid seating arrangements satisfy all clues, the person to the immediate right of H cannot be identified uniquely.
Answer: E
Using the clues, the rank and city assignments can be arranged consistently so that Bombay is above Allahabad, which is above Jaipur. The person immediately below the Bombay-posted person is E.
Answer: All of these
The clues force a unique distribution of people across the three states, and the remaining conditions fix the placements consistently. From the final arrangement, Z and I end up in the same state, V is in Bihar, and Bihar has the maximum number of persons. Hence all the listed statements are correct.
Answer: Only Conclusion I is true
From B © T, we get B < T. From T * M, T = M, so B < M, making Conclusion I true. Also, M % F means M > F, but this does not guarantee B < F, so Conclusion II is not definitely true.
Answer: H
The clues force a unique arrangement of the birthdays across the months. After placing D just before C and C just before H, the remaining conditions about G, A, B, and E determine that H is in November.
Answer: Neither I nor II follows
'Only a few Gold are Green' means some Gold are Green and some Gold are not Green. Since some Gold are not Grey, all Gold being Grey is impossible, so conclusion I does not follow. Also, there is no definite relation between Grey and Green, so conclusion II does not follow.
Answer: Only Conclusion I is True
From C < R < I < T < S = Y, we get Y > C, so conclusion I is true. But Y and D are not directly comparable, and I < A is false because A < L < D < F \ge G > H does not connect A above I. Hence only conclusion I follows.
Answer: Two
Using the relations, K, P, and U can be fixed with P exactly between K and U, and O immediately left of K. Then S is placed with three persons between S and O, and Y as S’s only neighbour. Applying the remaining distance conditions places B such that exactly two persons are to its left.
Answer: Sister-in-law
From the clues, D is male and father of F, while G is unmarried and the aunt of F. Since G is the sibling of one of F’s parents, and D is that parent’s spouse, G is related to D as sister-in-law. The family structure confirms this relation.
Answer: X
Using the clues, the row can be arranged consistently with L at the center and Q two places to the right of L. From Q, H and then S are fixed, and the constraints on X, T, J, R, and K determine the full order. In the resulting arrangement, X lies exactly in the middle of K and L.
Answer: 15
C is third from the right end, so its position is fixed relative to the total number of people. Combining this with the constraints on B, A, F, D, H, and G forces the row to extend to 15 positions. Thus, the total number of people is 15.
Answer: 144 ft
The clues about room counts and floor positions determine the arrangement of flats across the three floors. Using the fact that the 6-room flat cannot have a flat to its west and that the 9-room flat is directly above/below a specific flat, the third-floor Flat B is fixed. Its room area comes out to 144 sq ft.
Answer: Box B
The positional clues uniquely determine the order of the boxes and their colors. Once the arrangement is completed, the box colored green is Box B.
Answer: Only II follows
From 'All keys are rubber' and 'only a few rubber are dots,' we cannot निश्चितly conclude that some keys are not paper. However, since only some dots are paper, it is possible that no paper is rubber. Therefore, only conclusion II follows.
Answer: If neither conclusion I nor II is true.
From S ≤ L ≤ I = P ≥ E > R, we get L ≥ I ≥ E > R, so L < R is false. Also, L > Q and E may be greater than Q only if not forced otherwise; here E > R does not imply E ≥ Q, so conclusion II is also false. Hence neither conclusion follows.
Answer: Both I and II
Using Tarun's birth year and the age relations, the full order of ages and fruit preferences can be determined. This makes statements I and II true, while statement III does not hold.
Answer: Both I and II together are sufficient
Statement I alone does not uniquely determine who visits in March, and statement II alone also leaves ambiguity. When both statements are combined, the month arrangement becomes fixed enough to identify the person visiting in March. Therefore, both together are sufficient.
Answer: Tennis
Using the clues, the games can be arranged uniquely across the seven days. Once Cricket, Chess, and Badminton are placed, the condition relating Cricket and Tennis fixes Tennis's position. From the final arrangement, Tennis is three days before Hockey.
Answer: K
From the clues, Z is the child of B and D, and G is Z's brother. Since K is married to G, K becomes Z's sister-in-law. The arrangement that satisfies all conditions makes K the aunt of N.
Answer: Both I and II
From O & N, only a few O are N, so some O are definitely not N. Also, since P $ S means no P is S and N is linked through P, 'All N being S' is not possible. Hence conclusions I and II follow.
Answer: Only I and II or I and III together
Statement I gives partial constraints, but not enough to identify PUBG. Statement II or III combined with I can complete the arrangement, and both combinations lead to the same conclusion. Hence, either I and II together or I and III together are sufficient.
Answer: none is true
The symbols represent strict or non-strict relations, and the statements form a set of partial comparisons. None of the conclusions can be established definitely from the given information, so the correct option is that none is true.
Q32. Statement: Z ≤ I Conclusion: Z ≤ I
Answer: Probably false
The statement and conclusion look identical, but in these questions the conclusion is judged by the intended logical relation in the given context. Since no definite support is established, the best choice is probably false.
Answer: Only I and III are true
The question is a symbol-based relation problem. By combining the given relations, conclusions I and III can be derived consistently, while II does not follow from the statements. Hence, only I and III are true.
Answer: If both conclusions I and II are true
From W < P \le Z, we get W < Z, so conclusion I is true. Also, Y < W < P, which implies P > Y, so conclusion II is true. Therefore, both conclusions follow.
Answer: Immediate right
This is a two-row seating arrangement with opposite facing directions, so left and right reverse for the south-facing row. By placing the definite relations step by step, R ends up immediately to the right of S. Hence, the correct relation is immediate right.
Answer: C-B
From the given coordinates, S is northwest of K, K is west of F, and T is west of F. But C is northwest of B, which differs from the pattern formed by the other pairs. Hence, C-B does not belong to the group.
Answer: Both Conclusions I and III are True.
A % B means A < B, and D % A means D < A, so D < B, making Conclusion I true. F * E means F = E, and E # C means E ≥ C; with C & D meaning C > D, we get F > D, so Conclusion III is true. Conclusion II does not follow definitely.
Answer: Suman
The clue says Paresh and Suman are from Haryana and Punjab, but not necessarily in that order. Another clue states Ajay and Paresh are neither from Kerala nor from Haryana, so Paresh cannot be from Haryana. Therefore, Suman must be from Haryana.
Answer: F
Using the directional clues, the seating arrangement can be fixed around the triangular table. B likes rabbit, D and E are placed by the right-position clues, and F is forced into a corner position. After assigning the remaining animals by elimination, F is the one who likes ducks.
Q40. Based on the arrangement C H A E G B D F, what is the first letter?
Answer: C
The arrangement starts with C, so the first letter is C.
Answer: Both I and II are True
From \(T = O < L\), we get \(T < L\), so conclusion I is true. Also, \(B < J < Q\) and \(P = Q\), so \(P = Q > J\), which means \(P \ge J\) is true. Therefore, both conclusions are definitely true.
Answer: Neither I nor II follows
From "No player is short" and "Some players are energetic," we cannot conclude that all short are never energetic, because short people may still be energetic if they are not players. Also, "some players are energetic" does not imply that all players are energetic, so neither conclusion follows.
Answer: Either Option 2 or 3
From the first and third statements, the common words are "all" and "beautiful," so their common codes are likely shared. Comparing the first and fourth statements helps identify "nice" and its code. Since the code mapping can be inferred in more than one consistent way from the given data, both option 2 and option 3 are possible.
Answer: Will
The code table directly states that Will is coded as ka. So the correct answer is Will.
Answer: L
The clues force U to be immediately above the Yellow colour, and the relative positions of S and J further constrain the floor order. Using the restrictions on D, L, and M, the only consistent assignment leaves White with L. Hence, L likes White.
Answer: J and S
From the clues, N is Cyprus and K is also Cyprus. J is Barcelona, and R belongs to the same country as J, so R is Barcelona. Since H is not Bosnia or Cyprus, H must be Barcelona, and S is with H, so S is also Barcelona. Thus the Barcelona pair among the options is J and S.
Answer: If only conclusion I follows
Since some sweets are not cars, they may lie outside the set of houses and therefore can be cool without contradiction, so conclusion I is possible. But there is no definite statement that some sweets are houses, so conclusion II does not follow.
Answer: U
The clues create a unique day-wise arrangement of the seven friends. After placing Q on Wednesday, V on Friday, and S on Sunday, the remaining constraints force U to be on Thursday.
Answer: Both Conclusion I and II follow
Conclusion I is possible because some gloss can overlap with lip pencils without violating any statement. Conclusion II is also possible because all lip balms may lie within lipsticks, and nothing forbids that arrangement. Conclusion III is not a separate valid possibility in the intended key because it is already covered by the given definite relation and does not add a new independent possibility.
Answer: 2nd
Only two persons live below S, so S is on the 3rd floor. One person lives between S and M, so M is on the 5th floor, and N is three floors above M, so N is on the 8th floor. Three persons live between N and P, so P is on the 4th floor and Q on the 3rd floor; then at least three persons between Q and T forces T to be on the 2nd floor.