Exams › IBPS PO › Quantitative Aptitude
Passage: Two equations I and II are given. Solve both equations and mark the appropriate answer. I. $x^2 + 9x + 20 = 0$ II. $8y^2 - 15y + 7 = 0$ What is the relationship between $x$ and $y$?
- x > y
- x < y
- x ≥ y
- x ≤ y
Correct answer: x < y
Solution
Solving $x^2+9x+20=0$ gives $x=-4,-5$. Solving $8y^2-15y+7=0$ gives $y=1,\frac{7}{8}$. Since every possible value of $x$ is less than every possible value of $y$, the relation is $x<y$.
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