Exams › IBPS PO › Quantitative Aptitude
In each of the following questions, two equations are given. Solve both equations and give the answer: (i) $x^2 = 196$ (ii) $y^2 + 2y - 48 = 0$
- if $x > y$
- if $x \ge y$
- if $x = y$ or no relation can be established between $x$ and $y$
- if $x \le y$
Correct answer: if $x = y$ or no relation can be established between $x$ and $y$
Solution
From $x^2=196$, we get $x=\pm 14$. From $y^2+2y-48=0$, we get $(y+8)(y-6)=0$, so $y=6$ or $y=-8$. Since the possible values of $x$ and $y$ do not give a unique comparison in all cases, no definite relation can be established.
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