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ExamsIBPS POQuantitative Aptitude

Given the data regarding three automatic toys on two types of movements: Neck movements (NM) and Hand rotations (HR), answer the following. Toy A: Battery capacity = 1500 units, battery percentage = 80%. At every 4th NM and 3rd HR together, 1 unit of battery is consumed. Toy A gets completely discharged at 11 AM. Toy B: Battery capacity = 2000 units, battery percentage = 75%. NM = 30/min, HR/min = 50% of NM/min of Toy A. At every 3rd NM and 2nd HR together, 1 unit of battery is consumed. Toy C: Battery capacity = 120% of the battery capacity of Toy B, battery percentage = 60%. NM/min = NM/min of Toy A + 5, HR = 30/min. At every 3rd NM and 2nd HR together, 1 unit of battery is consumed. If power consumed per NM of Toy B is 0.1 unit, then what is the power consumed per HR of Toy B on that day?

  1. 0.45 unit
  2. 0.35 unit
  3. 0.15 unit
  4. 0.2 unit

Correct answer: 0.2 unit

Solution

For Toy B, the number of hand rotations per minute is 50% of Toy A's NM rate, so the movement counts are linked. Given the power consumed per NM is 0.1 unit and the total consumption pattern is fixed, the corresponding power per HR comes out to 0.2 unit.

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