Series: 5 7 3 4 5 4 6 2 1 7 8 9 2 4 6 8 4 3 8 9 3 6 What is the sum of odd numbers placed between the numbers which are 4th from both ends?

Correct answer: 25

Solution

22-term series: 4th from left=pos 4=4; 4th from right=pos 19=8. Numbers between (pos 5 to 18): 5,4,6,2,1,7,8,9,2,4,6,8,4,3. Odd numbers: 5,1,7,9,3. Sum = 5+1+7+9+3 = 25.

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