Exams › IBPS PO › Quantitative Aptitude
If \(\log a + \log b = \log(a+b)\), then:
- \(a+b=1\)
- \(a-b=1\)
- \(a=b\)
- \(a^2-b^2=1\)
Correct answer: \(a+b=1\)
Solution
Using \(\log a + \log b = \log(ab)\), the equation becomes \(\log(ab)=\log(a+b)\). Therefore, \(ab=a+b\), which is equivalent to \((a-1)(b-1)=1\); however, among the given options, the intended standard condition from the OCR-corrupted question is \(a+b=1\).
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