Exams › IBPS PO › Quantitative Aptitude

If \(\log 27 = 1.431\), then the value of \(\log 9\) is:

1. 0.934
2. 0.945
3. 0.954
4. 0.958

Correct answer: 0.954

Solution

Since \(27=3^3\), we have \(\log 27 = 3\log 3 = 1.431\). So \(\log 3 = 1.431/3 = 0.477\). Then \(\log 9 = \log(3^2)=2\log 3 = 2\times 0.477 = 0.954\).

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