What value will come in place of the question mark in the following equation? \[ \frac{7}{14} \times 266 + \frac{19}{57} \times 327 + 30\% \text{ of } 1960 = ? - 340 \]

1155
1240
1110
1170

Correct answer: 1170

Solution

Simplify term by term: \(\frac{7}{14}\times 266 = 133\), \(\frac{19}{57}\times 327 = 109\), and \(30\%\) of 1960 is 588. Their sum is 830, so \(? - 340 = 830\), giving \(? = 1170\).

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