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ExamsGATETechnical

The source of a silicon b7n-channel MOS transistor has an area of 1 sq mm and a depth of 1 b5m. If the dopant density in the source is $10^{19}\,\text{cm}^{-3}$, the number of holes in the source region with the above volume is approximately

  1. $10^7$
  2. 100
  3. 10
  4. 0

Correct answer: 0

Solution

For an n-type region, the hole concentration is the minority carrier concentration, given by $p=n_i^2/N_D$. Here $p=(10^{10})^2/10^{19}=10^1\,\text{cm}^{-3}$, and the source volume is $1\,\text{mm}^2\times 1\,\mu\text{m}=10^{-2}\,\text{cm}^2\times 10^{-4}\,\text{cm}=10^{-6}\,\text{cm}^3$. Thus the number of holes is $10\times 10^{-6}=10^{-5}$, which is approximately zero.

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