Exams › SSC CGL (Prelims) › Maths › Averages
12 questions with worked solutions.
Answer: 76 kg
If the average weight of 8 men increases by 2 kg, the total weight increases by 8 × 2 = 16 kg. Since one 60 kg man is replaced, the new man's weight must be 60 + 16 = 76 kg.
Q2. The average of the first five multiples of 6 is:
Answer: 18
The first five multiples of 6 are 6, 12, 18, 24, and 30. Their sum is 90, and dividing by 5 gives 18. So the average is 18.
Answer: ₹ 80
The total spent by 7 children is 7 × 120 = 840. The boys spent 4 × 150 = 600, so the girls spent 840 - 600 = 240; dividing by 3 gives 80.
Answer: 26
The sum of 9 observations is 9 × 16 = 144. The sum of 10 observations is 10 × 17 = 170, so the 10th observation is 170 - 144 = 26.
Answer: 6.5
For eight successive numbers, the average is the midpoint of the sequence. Therefore, the average of the smallest and greatest numbers is the same as the average of all eight numbers. Hence it is 6.5.
Answer: Increased by 1
If the five consecutive integers are \(x-2, x-1, x, x+1, x+2\), their average is \(x=n\). Adding the next two integers gives \(x+3\) and \(x+4\), so the new average becomes \(x+1\). Thus the average increases by 1.
Q7. The average of the first nine integral multiples of 3 is:
Answer: 15
The first nine multiples of 3 are 3, 6, 9, 12, 15, 18, 21, 24, 27. Their average is the midpoint of 3 and 27, which is 15.
Q8. The average of odd numbers up to 100 is:
Answer: 50
The odd numbers up to 100 are 1, 3, 5, ..., 99. This is an arithmetic progression, so its average is the midpoint of the first and last terms: \((1+99)/2=50\).
Q9. The average of nine consecutive odd numbers is 53. The least odd number is:
Answer: 45
For nine consecutive odd numbers, the average is the 5th term. So the middle number is 53. The least odd number is 4 steps below it: \(53-8=45\).
Answer: 21
Let the total number of workers be \(n\). Then total salary is \(8000n\). The 7 technicians earn \(7\times 12000=84000\), and the remaining \(n-7\) workers earn \(6000(n-7)\). Equating totals gives \(8000n=84000+6000(n-7)\), so \(n=21\).
Answer: 60
Let the third number be \(x\). Then the first number is \(3x\) and the second is \(\frac{3x}{4}\). Their average is 95, so \(\frac{3x+\frac{3x}{4}+x}{3}=95\), which gives \(x=60\).
Answer: 9
Let the third number be \(x\). Then the second is \(2x\) and the first is \(4x\). Their average is \(\frac{4x+2x+x}{3}=21\), so \(7x=63\) and \(x=9\). The smallest number is 9.