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The average of the first nine integral multiples of 3 is:

1. 12
2. 15
3. 18
4. 21

Correct answer: 15

Solution

The first nine multiples of 3 are 3, 6, 9, 12, 15, 18, 21, 24, 27. Their average is the midpoint of 3 and 27, which is 15.

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