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A circular coil ABCD carrying a current i is placed in a uniform magnetic field. If the magnetic force on the segment AB is F̅, the force on the remaining segment BCDA is

1. F̅
2. -F̅
3. 3F̅
4. -3F̅

Correct answer: -F̅

Solution

In a uniform magnetic field, the net force on a current-carrying closed loop is always zero because the forces on opposite segments cancel out. Thus, the force on the remaining segment BCDA must be equal and opposite to the force on AB, i.e., -F̅.

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