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A proton carrying 1 MeV kinetic energy is moving in a circular path of radius R in uniform magnetic field. What should be the energy of an α-particle to describe a circle of same radius in the same field?
- 2 MeV
- 1 MeV
- 0.5 MeV
- 4 MeV
Correct answer: 2 MeV
Solution
The radius of a charged particle in a magnetic field depends on its momentum and charge. Since the α-particle has twice the charge and four times the mass of a proton, its energy must be 2 MeV to maintain the same radius.
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